18x^2-27x-56=0

Solution for 18x^2-27x-56=0 equation:

18x^2-27x-56=0

a = 18; b = -27; c = -56;
Δ = b2-4ac
Δ = -272-4·18·(-56)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-69}{2*18}=\frac{-42}{36}
=-1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+69}{2*18}=\frac{96}{36}
=2+2/3
$